Calling a function from another folder

Lolzen · 10-31-16, 04:11 AM

I'd like to call a function from another folder.
Thought this would work, apparently it is restricted to files inside AA's folder. What do i have to do to be able to call AA's function on BB?
BB has AA as dependency.

addon 1: AA, addon2: BB

AA.lua

Code:

addon, ns = ..

ns.test = "TEST"

BB.lua

Code:

print(AA.test)

Phanx · 10-31-16, 04:21 AM

In order for one addon to access another's functions/variables/tables/anythings, you must put those things into the global namespace:

Code:

local addon, ns = ...
ns.test = "TEST"

_G[addon] = ns

...or, less indiscriminately, if you only need certain things to be accessible:

Code:

local addon, ns = ...
ns.test = "TEST"

_G[addon] = {
    test = ns.test
}

Either way, you can then to do this in other addons:

Code:

print(OtherAddon.test)

Lolzen · 10-31-16, 04:27 AM

Thanks a bunch, Phanx!

zork · 10-31-16, 08:40 AM

If you need to access that variable from the other addon when the addon is initialized make sure you define the addon as a dependency.

Example from my addons. oUF_SimpleConfig is the config for oUF_Simple.

Code:

oUF_SimpleConfig = L.C

https://github.com/zorker/rothui/blo...g/init.lua#L17

Code:

## Dependencies: rLib, oUF_SimpleConfig

https://github.com/zorker/rothui/blo...oUF_Simple.toc

Code:

--get the config
L.C = oUF_SimpleConfig

https://github.com/zorker/rothui/blo...e/init.lua#L16

Lolzen · 10-31-16, 03:56 PM

Thank you too, Zork.

I actually used

Code:

_G[addon] = ns

Works fine and is pretty much what i wanted to do in the first place, but couldn't find a result on the web.